Question

1. Predict the approximate density of Cs from the following data
using law of triads
K = 0.868 cm Rb = 1.532 g cm. Cs=?
(a) 2.196 g cm
(b) 4.392 g cm
(c) 1.098 g cm
(d)None of these​

Answer 1

Answer:

option a is correct

Explanation:

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Answer 2

" It seems this is what you are looking for"

Predict the approximate density of Cs from the following data using law of triads,

K = 0.868g/cm³, Rb= 1.532 g/cm³, Cs=?, Ca = 1.548g/cm³, Ba= 3.51g/cm³, Sr = 2.63g/cm³ , Sc = 2.991g/cm³, Y= 4.34g/cm³ and La = 6.16g/cm³.

Answer:

The approximate density of Cs from the following data will be equal to  1.899 g/cm³.

Explanation:

The elements are given above are belong to:

The elements K, Rb and Cs are belong to group 1

The elements Ca, Ba and Sr are belong to group 2

The elements Sc, Y and La are belong to group 3.

We can find the density of Cs from the relative density of other elements.

Now, ratio of densities of Ba and Sr $=\frac{3.51}{2.63} =1.33$

Ratio of densities of Y and La $=\frac{6.16}{4.34}=1.42$

From group2 to group3, ratio increase by $=1.42-1.33=0.09$

In similar way, the expected ratio density of Cs and Rb $=1.33-0.09=1.24$

Thus, $\frac{Density\; of\; Cs}{Density\; of \; Rb}=1.24$

Density of Cs = 1.24×1.532 = 1.899gcm⁻³