1. principal =Rs.1000;Rate=Rate=13% p.a; Time = 2 year.
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Hi !!!
This is your answer
.....
Given :----
Principal = Rs. 1000.
Rate of interest = 13% pa
Time = 2 years.
The question seems incomplete......
But, I guess you wanted to ask SI or Amount....
So,
![si = \frac{p \times r \times t}{100} \\ = \frac{1000 \times13 \times 2 }{100} \\ = 10 \times 26 \\ = 260 si = \frac{p \times r \times t}{100} \\ = \frac{1000 \times13 \times 2 }{100} \\ = 10 \times 26 \\ = 260](https://tex.z-dn.net/?f=si+%3D+%5Cfrac%7Bp+%5Ctimes+r+%5Ctimes+t%7D%7B100%7D+%5C%5C+++%3D++%5Cfrac%7B1000+%5Ctimes13+%5Ctimes+2+%7D%7B100%7D+%5C%5C+++%3D+10+%5Ctimes+26+%5C%5C++%3D+260)
Hence, the simple interest is Rs. 260 and the amount is 260+1000 = Rs. 1260.
Hope you got the answer
......
This is your answer
.....
Given :----
Principal = Rs. 1000.
Rate of interest = 13% pa
Time = 2 years.
The question seems incomplete......
But, I guess you wanted to ask SI or Amount....
So,
Hence, the simple interest is Rs. 260 and the amount is 260+1000 = Rs. 1260.
Hope you got the answer
......
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