Question

1. Program to find sum of series 1 + 1/2 + 1/3 + 1/4 +...+ 1/n.

Answer 1

Explanation:

#include <iostream>

using namespace std;

Function to return sum of

1/1 + 1/2 + 1/3 + ..+ 1/n

{

double sum(int n)

{

double i, s = 0.0;

for (i = 1; i <= n; i++)

s = s + 1/i;

return s;

}

};

int main()

{

gfg g;

int n = 5;

cout << "Sum is " << g.sum(n);

return 0;

}