1. Prove that (1 + tan A - sec A) x (1 + tan A + sec A) = 2 tan A.
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Answer:
L.H.S. = ( 1 + tan A - sec A ) × ( 1 + tan A + sec A )
= 1 + tan A + sec A + tan A + tan²A + tan A sec A - sec A - tan A sec A - sec²A
= 1 + 2 tan A + tan²A - sec²A
= 1 + 2 tan A -1
= 2 tan A
R.H.S. = 2 tan A
so, L.H.S. = R.H.S.
( 1 + tan A - sec A ) × ( 1 + tan A + sec A ) = 2 tan A
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