1) Prove that 3-2√5 is irrational?
2) Prove that 7-√2 is irrational?
3) Prove that 2+√7 is irrational?
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Answered by
61
➡️ 1) let 3-2√5 be a rational no.
so, 3-2√5 = a/b
√5 = a/2b - 3
a/2b-3 is a rational number
so, √5 also a rational no.
but, a qontradiction fact is that √5 is an irrerational no.
so, 3-2√5 is an IRRERATIONAL no. ❤️
similar you can do remaining 2 ❤️
ALL THE BEST FOR YOUR BOARDS ❤️✌️
Answered by
27
Answer:
Let us assume ,
3+2√5 is rational.
So , 3+2√5 = a/b
a and b are coprimes
2√5 = a/b -3
√5 = a-3b /2b
Thus implies , √5 is rational which is incorrect . ( a and b are coprimes)
Thus our assumption that 3+2√5 is rational is incorrect.
So , 3+2√5 is irrational .
Hope it help you ✌️❣️
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