1. Prove that
5 is irrational.
No spam please
Answers
Answered by
0
Answer:
answer photo me hai bro
Attachments:
Answered by
2
Answer:
Let √5 be rational number.
let √5 = a/b , where b ≠ 0 & a and b are co prime integers.
b√5 = a
sq on both sides.
5b² = a²
therefore, a² is divisible by 5,
that implies a is divisible by 5. -------------eqn 1
so , a = 5m
a² = 25m²
frm eqn 1,
5b² = 25m²
b² = 5m²
therefore b² is divisible by 5
that implies b is divisible by 5. ---------------eqn 2
from eqn 1 & 2,
a and b are divisible by 5,
but we assumed that a & b are co prime Integers
therefore, our assumption is incorrect.
hence, √5 is irrational.
H,P
hope it helped!
Similar questions