Question

1) prove that
Angle BAC =90°​

Answer 1

Step-by-step explanation:

given that AD square =BD×DC

TO PROVE Angle BAC=90°

PROOF

AD×AD = BD×DC............1

Now using Pythagoras theorem in triangle ADB

AB×AB=AD×BD

AB÷AD=BD÷AD............2

ON comparing eq 1 and 2

AD÷ DC= BD÷AD.......3

and, angle B Is equal to the Angle B

ie triangle ABC~DBA