Question

1. Prove that CE bisect <C
2. Describe how this can be used to divide an 8cm long line in the ratio 4:5.
3. Can we use it to divide an 8cm long line in the ratio 3:4 ? How ?
Atleast , answer me the 3rd question
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Answer 1

Answer:

1. ∆ BCD is an equilateral triangle If∠CBD = x then ∠CDB = x

∠BCD = 180 – 2x

∠BCE = x

(line BC passing through parallel lines EC and BD makes equal angle)

∴ ∠ACE = x

∴ line CE bisects ∠C.

2. If AB = 8, AC = 4, and CB = 5

then the line CE divides AB in the ratio 4 : 5.

3. No.

We can’t draw a triangle with sides 8cm, 3cm and 4cm. Since 3 : 4 = 6 : 8, take 6cm and 8cm as two sides then find third side.