Question

1 Prove that (cosec 0 - sin o) (sec 0 - cos 0) (tan 0 + cot o) = 1​

Answer 1

Answer:

let, LHS= (cosec 0 - sin 0) (sec 0 - Cos 0) (tan0+cot0)

= (1 ➗ sin0-sin0) (1 ➗ cos0-cos 0) (tan0+1 ➗ tan 0)

= 0 x 1 - 1 x 0 + 0

= 1-1 x 0 + 0

=1-0+0

=1-0

=1

=RHS

hence, LHS = RHS