1 . Prove that equal chords of a circle subtend equal angle at the centre.
2. Prove that if chords of congruent circles subtend equal angles at their centers, then the chords
are equal.
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Answers
- In ΔAOB and ΔCOD,
AB=CD (Given)
AO=CO (radius)
OB=OD (radius)
By S.S.S congruency, ΔAOB≅ΔCOD
⇒∠AOB=∠COD.
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In △AOB and △PXQ
In △AOB and △PXQAO=PX [Radius of congruent circles are equal]
In △AOB and △PXQAO=PX [Radius of congruent circles are equal]∠AOB=∠PXQ [Given]
In △AOB and △PXQAO=PX [Radius of congruent circles are equal]∠AOB=∠PXQ [Given]BO=QX [Radius of congruent circles are equal]
In △AOB and △PXQAO=PX [Radius of congruent circles are equal]∠AOB=∠PXQ [Given]BO=QX [Radius of congruent circles are equal]△AOB≅△PXQ [SAS congruence rule]
In △AOB and △PXQAO=PX [Radius of congruent circles are equal]∠AOB=∠PXQ [Given]BO=QX [Radius of congruent circles are equal]△AOB≅△PXQ [SAS congruence rule]∴AB=PQ [CPCT]
NOTE
- IMAGE 1 FOR ANSWER 1
- IMAGE 2 FOR ANSWER 2