1. Prove that:
tan²A/(Sec A-1)²= 1+cos A/ 1-cosA
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Answer:
for the answer see in the master key
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Answer:
sec^2-1/(secA-1)(secA-1)
Step-by-step explanation:
(secA+1)(secA-1)/(secA-1)(secA-1)=(secA+1)/(secA-1)=(1/cosA+1)/(1/cosA-1)=1+cosA /1-cosA
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