Question

1. Prove that:
tan²A/(Sec A-1)²= 1+cos A/ 1-cosA
​

Answer 1

Answer:

for the answer see in the master key

Answer 2

Answer:

sec^2-1/(secA-1)(secA-1)

Step-by-step explanation:

(secA+1)(secA-1)/(secA-1)(secA-1)=(secA+1)/(secA-1)=(1/cosA+1)/(1/cosA-1)=1+cosA /1-cosA