Question

1
Prove that ZCOD = (ZA + ZB).
2
4. In a quadrilateral ABCD, CO and DO are the bisectors of ZC and ZD respectively​

Answer 1

Answer:

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Step-by-step explanation:

In △COD,

∠COD+∠1+∠2=180

o

∠COD=180

o

−(∠1+∠2)

∠COD=180

o

−

2

1

(∠C+∠D)

∠COD=180

o

−

2

1

[360

o

−(∠A+∠B)]

∠COD=

2

1

(∠A+∠B)