--- 1. Prove the following relations for position vector 1 = xi + yj + zk: (i) 5 73 (ii) (r) = f (iii) 7 8=3 (iv) Txi=0
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Step-by-step explanation:
3( 3 x - 4 y ) ^ { 2 } - 25 z ^ { 2 }(3x−4y)
2
−25z
23( 3 x - 4 y ) ^ { 2 } - 25 z ^ { 2 }(3x−4y)
2
−25z
24( 3 x - 4 y ) ^ { 2 } - 25 z ^ { 2 }(3x−4y)
2
−25z
2( 3 x - 4 y ) ^ { 2 } - 25 z ^ { 2 }(3x−4y)
2
−25z
2( 3 x - 4 y ) ^ { 2 } - 25 z ^ { 2 }(3x−4y)
2
−25z
2( 3 x - 4 y ) ^ { 2 } - 25 z ^ { 2 }(3x−4y)
2
−25z
2( 3 x - 4 y ) ^ { 2 } - 25 z ^ { 2 }(3x−4y)
2
−25z
2
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