Question

(1) Prove the following: sec 0 (1 - sin 0) (sec 0+tan ) = 1
LHS =sec (1 - sin o) (sec @+ tan e)
= x(1 - sin 8)x
MY
(
1
+1
(coso
(1-sin 8)
cose
(D
)
cos @
cose
= (a + b)(a+b)=x-by academy.co.
= 1 : 1 - sin® A-cora, e only do na
cos? o
[ sinA +cos? A=1.1 - sin" A=cos A)
LHS=1
RHS = 1
* LHS = RHS
- sec (1 - sin o) (sec 0 + tan 8) = 1
monte of a circle with centre a​

Answer 1

Answer:

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