Question

1)q-1/2=4-q
2)A number is divided into two parts,one part being 4 times the other .The difference between the two parts is 15.What is the number​

Answer 1

Required Answers:

(Question 1)

To solve:-

• q- 1/2 = 4 - q

Here are the steps:

⇒ q - 1/2 = 4 - q

⇒ q + q = 4 + 1/2

⇒ 2q = 9/2

⇒ q = 9/4

Therefore:-

• The required value of q is 9/4 (Ans)

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(Question 2)

GiveN:-

• A number is divided into two parts, one part being 4 times the other.
• The difference between the two parts is 15$.$

To FinD:-

• What is the number?

Solution:-

Let the number be x. And the parts be a and b. Then we should remember that a + b = x.

According to first condition,

• First part = 4(Second part)

⇒ a = 4b --------(1)

According to second condition,

• Difference between the parts is 15.

⇒ a - b = 15

⇒ 4b - b = 15 (......from 1)

⇒ 3b = 15

⇒ b = 5

Then, a = 20

Hence:-

• The required number is a + b = 20 + 5 = 25

Answer 2

Required Solution:

(Question 1)

➡ Solve the given linear equation, q - 1/2 = 4 - q

(Solution)

Given linear equation,

$\sf q - \frac{1}{2} = 4 - q$

$\sf \implies q + q = 4 + \frac{1}{2}$

$\sf \implies 2q = \frac{8 + 1}{2}$

$\sf \implies 2q = \frac{9}{2}$

$\sf \implies q = \frac{9}{2 \times 2}$

$\sf \implies q = \frac{9}{4}$

$\sf \implies q = 2\frac{1}{4}$

Hence, the required value of q is 2.25

(Question 2)

➡ A number is divided into two parts,one part being 4 times the other .The difference between the two parts is 15. Find the number.

(Solution)

Let the number x be divided into two parts such that,

First part = a and

Second part = b

Therefore,

➡ a + b = x

Its given that,

➡ a = 4b (First part is 4times the other)

Now, find out the difference,

➡ a - b = 15

Substitute the value of a here,

➡ 4b - b = 15

➡ 3b = 15

Divide both sides by 3,

➡ b = 5

Hence, value of b is 5.

Now,

a = 4 × b

= 4 × 5

= 20

Therefore, the values of a and b are 20 and 5.

x = 20 + 5

➡ x = 25

Hence, the number is 25.

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