1
Q3-4) The First term of an A.P
is 6 and the common
difference is 3.
*
Find S10
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3
Answer:
Sn = (n/2) × 2a + ( n - 1 )d
S10 = (10/2) × [ 2×6 + ( 10 - 1 ) 3 ]
= 5 × ( 12 + 27 )
= 5 × 39
= 195
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