Question

1
Q3-4) The First term of an A.P
is 6 and the common
difference is 3.
*
Find S10​

Answer 1

Answer:

Sn = (n/2) × 2a + ( n - 1 )d

S10 = (10/2) × [ 2×6 + ( 10 - 1 ) 3 ]

= 5 × ( 12 + 27 )

= 5 × 39

= 195