Math, asked by renubishnoi94683, 6 months ago

1
Q6) The perimeter of a
rhombus is 20 cm. If one of its
diagonals is 6 cm, then its area
is *​

Answers

Answered by udeeksha
4

Answer:

let the first diagonal d

let the second diagonal d2

perimeter of rhombus 20 cm

we know the perimeter of rhombus 4 side

side = 20÷4

5 cm

now, we know that the diagonal of a rhombus bisect each other at right angles (90)

Hence, a right angles triangle can be visualised with the side as hypothesis

diagonal length is 6 cm

half the length (since diagonal bisect each other)

6÷2 =3

(d/2)²+(d/2)² = 5²cm

(6/2)²+(d/2) = 25cm

3² + (d/2) = 25 cm

(d/2) = 25-6 cm

(d/2) = 19 cm

(d/2) =√19

(d/2) = 4.3 cm

Hence other diagonal is 4.3

Area =½×d×d

½×6×4.3

24cm square

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