Question

1 quujuuli Lallius 2 malRs.
Find the circle equation concentric with x² + y2 - 6x - 4y+2 and passing through (-2, 4)​

Answer 1

Step-by-step explanation:

Equation of concentric circle of x2+y2−6x−4y−12=0 is given by,

(x−3)2+(y−2)2=r2, since center of both circle will be same.

Now above circle is passing through (−2,14), so put this point in the circle

⇒(−2−3)2+(14−2)2=r2⇒r2=169 

Hence the required circle is,

(x−3)2+(y−2)2=132