Question

1÷(r-a)^2-1÷(r+a)^2​

Answer 1

Answer:

1/(r-a)^2-1/(r+a)^2=

take lcm we get [(r-a)^2-(r+a)^2]/[(r-a)(r+a)]^2

after solving denominator and neuminator we get

4ra/(r^2-a^2)^2