Question

1. Rationalise the denominator 2√2 upon 3-7√5​

Answer 1

Step-by-step explanation:

$sol {}^{n}$

$\frac{2 \sqrt{2} }{ 3 - 7 \sqrt{5} }$

$= \frac{2 \sqrt{2}(3 + 7 \sqrt{5)} }{(3 - 7 \sqrt{5)}(3 + 7 \sqrt{5)} }$

$= \frac{6 \sqrt{2} + 14 \sqrt{10} }{ {3}^{2} - (7 \sqrt{5}) {}^{2} }$

$= \frac{6 \sqrt{2} + 14 \sqrt{10} }{9 - 245}$

$= \frac{6 \sqrt{2} + 14 \sqrt{10} }{ - 236}$

$= \frac{3 \sqrt{2} + 7 \sqrt{10} }{ - 118}$

$= - \frac{3 \sqrt{2} + 7 \sqrt{10} }{118}$