Math, asked by roshanhosmani8, 3 months ago

1 Rationalise the denominator of 7_ J,/​

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Answered by shashi1979bala
0

\large\blue{\sf{SOLUTION-}}

=\large{\sf{ \frac{1}{7 - 3 \sqrt{3} } }}

=\large{\sf{ \frac{1}{7 - 3 \sqrt{3} }  \times  \frac{7 +  3\sqrt{3} }{7 + 3 \sqrt{3} } }}

=\large{\sf{ \frac{7 +  3\sqrt{3} }{(7 ) {}^{2}  - ( 3 \sqrt{3}) {}^{2}  } }}

=\large{\sf{ \frac{7 +  3\sqrt{3}} { 49 - 27 } }}

=\large{\sf{ \frac{7 +  3\sqrt{3}} { 22 } }}

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