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Rationalize the denominator of 1/ root3_root2
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Answer:
Answer:
\sqrt{3} + \sqrt{2}3+2
Step-by-step explanation:
1/\sqrt{3} - \sqrt{2}3−2 *\sqrt{3} + \sqrt{2}3+2 /\sqrt{3} + \sqrt{2}3+2 =
\sqrt{3} + \sqrt{2}3+2 /3-2 =
\sqrt{3} + \sqrt{2}3+2 /1 =
\sqrt{3} + \sqrt{2}3+2
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