1 rectangular room of dimension 8 mx 6 mx 3 m is to be painted. If it costs < 60 per square m
find the cost of painting the walls of the room.
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Answer:
According to the question , the length of the room (l) is 8 m, the breadth of the room (b) is 6 m and the height of the room (h) is 3 m.
Step-by-step explanation:
The area of the walls that is to be painted is l b + b h + l b + b h
that is, 2( l b + b h)
= 2 ( 8 * 6 + 6 *3)
=2 ( 48 + 18)
= 2 (66)
= 132 m²
Given that the cost of painting 1 m² = Rs 60
Now, the cost of painting 132 m² = Rs 132 * 60 = Rs 7920.
Hence , the answer is Rs 7920.
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