Question

1. Reduce the following Boolean Expression Based on Law
a) W=ABC+CAB+BAC
b) X=ABC+ABC'
c) W=X (X'YZ+X’YZ
d) W=AB (A'C+B)
e) Z=AB'C'+AB'C+A'BC+A'B'C
f) W=(X1+X2) (X1'+X1X2) +(X2'+X1X2')
g) A=WXY (WX'+WY') +WX'Y (W'X'+XY')
h) Y=ABC+AB+A
i) Y= [AB'(C+BD) +A'B'] C
j) Y= (AB+AC)'+A'B'C
k) F:X'YZ+XY’Z+XYZ+XYZ​

Answer 1

Answer:

answer is w = AB (A' C + B ) this is your answer