1. Reduce the following Boolean Expression Based on Law a) w=x(x'yz+x'yz')
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L.H.S. = (X + Y)(X + Z) = XX + XZ + XY + YZ = X + XZ + XY + YZ (XX = X Indempotence law) = X + XY + XZ + YZ = X(1 + Y) + Z(X + Y) = X.1 + Z(X + Y) (1 + Y = 1 property of 0 and 1) = X + XZ + YZ) (X . 1 = X property of 0 and 1) = X(1 + Z) + YZ = X.1 + YZ (1 + Z = 1 property of 0 and 1) = X.1 + YZ (X . 1 = X property of 0 and 1) = L.H.S. Hence provedRead more on Sarthaks.com - https://www.sarthaks.com/439644/prove-algebraically-that-x-y-x-z-x-yz
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