Question

1. Rene is 6 years older than her younger sister. After 10 years, the sum of their ages
will be 50 years. Find their present ages.

Answer 1

Answer:

Here!

Step-by-step explanation:

let the age of Rene's sister be X

Age of Rene= X+6

After 10 years,

Rene age= X+16

Rene's  younger sister's age = X+10

ATQ,

X+16+X+10=50

2X=24

X=12(Rene's Sister)

X+6=18(Rene's age)

Answer 2

Answer:

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Step-by-step explanation:

Rene at present is 18 years old and her younger sister is 12 years old. Thus after 10 years, Rene will be 28 years old and her younger sister will be 22 years old and thus total of their ages would be 50.