Question

1. Resolve into partial fractions: x/(x+1)(x+2)
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Answer 1

$\tt Let\: \frac{x}{(x+1)(x+2)} = \frac{A}{x+1} + \frac{B}{x+2} \\ \\ \tt \therefore x = A(x+2) + B(x+1) \\ \\ \tt Put\:x=-1 \:we \:get \\ \\ \tt \therefore -1 = A(-1+2) + B(-1+1) \\ \\ \tt \therefore \boxed{\bold{\underline{\green{A = -1}}}} \\ \\ \tt Now\:put\:x=-2 \:we\:get \\ \\ \tt \therefore -2 = A(-2+2) + B(-2+1) \\ \\ \tt \therefore -B = -2 \\ \\ \tt \therefore \boxed{\bold{\underline{\green{\tt B = 2 }}}} \\ \\ \tt \therefore \boxed{\bold{\underline{\red{\tt \frac{x}{(x+1)(x+2)} = \frac{-1}{x+1} + \frac{2}{x+2} }}}}$

Answer 2

Answer:

hey frnd see the above pic for answer

I hope you get your answer

thnx for asking