1 rhombus shaped field has green grass for 18 cows to graze. If each side of the
hombus is 30 m and its longer diagonal is 48 m, how much area of grass field will each
ow be getting?
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Answered by
1
Step-by-step explanation:
Rhombus
Solve for area
A=864
a =side =30m
p= Diagonal = 48
Unit Conversion:
Using the formulas
A=pq
2
a=p2+q2
2
Solving forA
A=1
2p4a2﹣p2=1
2·48·4·302﹣482=864
Answered by
3
side of rhombus=30 m
longer diagonal=48 m
area of rhombus=
In triangle BCD
s=a+b+c/2
s= 30+30+48/2
s= 108/2
s=54
s-a=54-30=24
s-b=54-48=6
s-c=54-30=24
Area=√s(s-a) (s-b) (s-c)
√54×24×6×24
- Factorise the numbers
√2×3×3×3×24×24×2×3
- make the pair of same no. and out
it from square root
24×2×3×3
432m square
- similarly area of triangle ADC is equal to 432 square
- area of Rhombus ABCD equal to 432 x 2 =864 m square
- area of cow graze for one cow =total area÷total no. of cow
864÷18=48m square
one cow graze 48 m square
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