Math, asked by naveennk75, 11 months ago

1 rhombus shaped field has green grass for 18 cows to graze. If each side of the
hombus is 30 m and its longer diagonal is 48 m, how much area of grass field will each
ow be getting?​

Answers

Answered by useridaasim
1

Step-by-step explanation:

Rhombus

Solve for area

A=864

a =side =30m

p= Diagonal = 48

Unit Conversion:

Using the formulas

A=pq

2

a=p2+q2

2

Solving forA

A=1

2p4a2﹣p2=1

2·48·4·302﹣482=864

Answered by Ahinush
3

side of rhombus=30 m

longer diagonal=48 m

area of rhombus=

In triangle BCD

s=a+b+c/2

s= 30+30+48/2

s= 108/2

s=54

s-a=54-30=24

s-b=54-48=6

s-c=54-30=24

Area=√s(s-a) (s-b) (s-c)

√54×24×6×24

  • Factorise the numbers

√2×3×3×3×24×24×2×3

  • make the pair of same no. and out

it from square root

24×2×3×3

432m square

  • similarly area of triangle ADC is equal to 432 square
  • area of Rhombus ABCD equal to 432 x 2 =864 m square
  • area of cow graze for one cow =total area÷total no. of cow

864÷18=48m square

one cow graze 48 m square

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