Question

1.Rohan bought a rhombus shaped field,whose diagonals are 2400 m and 1000 m.Rohan wants to fence it but don’t know the length of its boundary 1.1.Which of the following is the length of side of field
A ) 1200 metres
B ) 1300 metres
C ) 1400 metres
D ) 1500 metres
1.2 What will be the cost of fencing the length of boundary of the field,If cost of fencing is 70 rupees per metre ?
A ) 3,36,000 Rupees
B ) 3,56,000 Rupees
C ) 3,64,000 Rupees
D ) 1,05,000 Rupees
1.3 What is the area of land Rohan bought ?
A) 12,00,000m^2
B ) 6,00,000 m^2
C ) 9,00,000 m^2
D ) 3,00,000 m^2
1.4 If the rate of land is Rs. x per square m, the cost will be_____
Rs. 2400000x
Rs. 1300000
Rs. 1200000
Rs. 1200000x
1.5 Which of the following statement is false?
All the squares are rhombus.
All the rhombus are squares.
Diagonals bisects perpendicularly in squares.
Diagonals bisects perpendicularly in rhombus.

Answer 1

Answer:

a) let ABCD be the sides and point O at which the diagonals meet

AO = 500 m

OC = 500 m

(Diagonals bisect each other)

BO = 1200 m

OD = 1200 m

(Diagonals bisect each other)

Each forms a right triangle inside so we can use Pythogorean theorm

a² + b² = c²

500² + 1200² = c²

=>2500 + 14400 = c²

=>16900 = c²

=> c = √16900

=> c = 130

b) perimeter = 4s

1 side = 130 m

Per meter = 70 rs

Perimeter = 130 x 4

                = 520 m

Cost = 520 x 70

       = 36400 rs

c) Area of rhombus = pq

/2

p = 2400 q = 1000

2400x1000/2 = 2400000/2

= 1200000 m²

Hope its helpful :D

Step-by-step explanation: