1/ root 2 + root 3+ root 5
Answer please.
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Answered by
5
hi Nikki,
here is your answer!!
1/(√2+√3+√5)
Rationalising factor = √2+√3-√5
→ 1/(√2+√3+√5) × (√2+√3-√5)/(√2+√3-√5)
→ (√2+√3-√5)/(√2+√3+√5)(√2+√3-√5)
→ (√2+√3-√5)/{(√2+√3)²-(√5)²}
→ (√2+√3-√5)/{√2²+√3²+2(√2)(√3) - 5}
→ (√2+√3-√5)/{2+3+2√6 - 5}
→ (√2+√3-√5)/2√6
The denominator is still irrational.
So we have to rationalise it further.
now,rationalising factor = √6
→ (√2+√3-√5)/2√6 × √6/√6
→ √6(√2+√3-√5)/2(√6)²
→ √12+√18-√30/2(6)
→ √4×3 + √9×2 - √30/12
→ (2√3+3√2-√30)/12
Hope it helps...
here is your answer!!
1/(√2+√3+√5)
Rationalising factor = √2+√3-√5
→ 1/(√2+√3+√5) × (√2+√3-√5)/(√2+√3-√5)
→ (√2+√3-√5)/(√2+√3+√5)(√2+√3-√5)
→ (√2+√3-√5)/{(√2+√3)²-(√5)²}
→ (√2+√3-√5)/{√2²+√3²+2(√2)(√3) - 5}
→ (√2+√3-√5)/{2+3+2√6 - 5}
→ (√2+√3-√5)/2√6
The denominator is still irrational.
So we have to rationalise it further.
now,rationalising factor = √6
→ (√2+√3-√5)/2√6 × √6/√6
→ √6(√2+√3-√5)/2(√6)²
→ √12+√18-√30/2(6)
→ √4×3 + √9×2 - √30/12
→ (2√3+3√2-√30)/12
Hope it helps...
Answered by
1
hope it helps you.. mark me as verified answer mam
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