Math, asked by Nikki57, 1 year ago

1/ root 2 + root 3+ root 5

Answer please.

Answers

Answered by snehitha2
5
hi Nikki,

here is your answer!!

1/(√2+√3+√5)

Rationalising factor = √2+√3-√5

→ 1/(√2+√3+√5) × (√2+√3-√5)/(√2+√3-√5)

→ (√2+√3-√5)/(√2+√3+√5)(√2+√3-√5)

→ (√2+√3-√5)/{(√2+√3)²-(√5)²}

→ (√2+√3-√5)/{√2²+√3²+2(√2)(√3) - 5}

→ (√2+√3-√5)/{2+3+2√6 - 5}

→ (√2+√3-√5)/2√6

The denominator is still irrational.

So we have to rationalise it further.

now,rationalising factor = √6

→ (√2+√3-√5)/2√6 × √6/√6

→ √6(√2+√3-√5)/2(√6)²

→ √12+√18-√30/2(6)

→ √4×3 + √9×2 - √30/12

→ (2√3+3√2-√30)/12

Hope it helps...
Answered by asuryavarsha2016
1

hope it helps you.. mark me as verified answer mam

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