Question

1 + root 2 upon 1 minus root 3 + 1 - root 2 upon 1 + root 3

Answer 1

-1-√6

Step-by-step explanation:

1+√2/1-√3 + 1- √2/ 1+√3

on taking the LCM, we get

(1+√2)(1+√3) + (1-√2)(1-√3)/ (1-√3)(1+√3)

=1+√3+√2+√6+1-√3-√2+√6/(1-√3)(1+√3)

on using the identity {a^2-b^2 = (a+b) (a-b)} in denominator

=2+2√6 / 1^2 - √3^2

= 2(1+√6) / 1 - 3

= 2( 1+√6) / -2

= -1-√6