Question

1/(root 3 + root 2 ) ×2 /root 3 - root2 )

Answer 1

$\frac{1}{ \sqrt{3} + \sqrt{2} } \times \frac{2}{ \sqrt{3 } - \sqrt{2} }$

=

$\frac{1 \times 2}{( \sqrt{3} + \sqrt{2}) \times ( \sqrt{3} - \sqrt{2} ) }$

now,

using( a^2-b^2) formula where (a=root 3 and b= root 2):

$\frac{1 \times 2}{( { \sqrt{3} })^{2} -( { \sqrt{2} })^{2} }$

=

$\frac{2}{3 - 2}$

=

$\frac{2}{1}$

= 1