Question

1/root 7 - root 6
rationalise it​

Answer 1

$\frac{1}{\sqrt{7}-\sqrt{6} }\\ \\=\frac{1}{\sqrt{7}-\sqrt{6} }*\frac{\sqrt{7}+\sqrt{6}}{\sqrt{7}+\sqrt{6}} \\\\=\frac{\sqrt{7}+\sqrt{6} }{(\sqrt{7} )^2-(\sqrt{6})^2 }\\ \\=\frac{\sqrt{7}+\sqrt{6} }{7-6 }\\\\=\frac{\sqrt{7}+\sqrt{6} }{1}\\\\=\sqrt{7}+\sqrt{6}$