Question

1 / root 9 -r root 8 is equal to
$a. \frac{1}{2} ( 3 - 2 \sqrt{2}$
$b.3 + 2 \sqrt{2}$
$c.3 - 2 \sqrt{2}$
$d. \frac{1}{3 + 2 \sqrt{2} }$
PLEASE ANSWER ANY MODERATOR OR ANY MATHS GENIUS WITH FULL EXPLAINATION. OTHERS WILL BE REPORTED. ^_^​

Answer 1

(d)3–2√2

✨Answer✨

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Answer 2

$\large{\underline{\underline{\bold{\red{\sf{Bonjour !}}}}}}$

$\frac{1}{ \sqrt{9} - \sqrt{8} } = \frac{1}{ \sqrt{9} - \sqrt{8} } \times \frac{ \sqrt{9} + \sqrt{8} }{ \sqrt{9} + \sqrt{8} }$

multiplying and dividing by conjugate of denominator

$\frac{ \sqrt{9 } + \sqrt{8} }{9 - 8} = \frac{3 - 2 \sqrt{2} }{1} = 3 - 2 \sqrt{2}$

$\large{\bold{\blue{\sf{thanks}}}}$