Question

1/root 9 - root 8 is equal to??
it is really urgent

Answer 1

${\huge{\pink{\underline{\underline{\purple{\mathbb{\bold{\mathcal{AnSwEr..}}}}}}}}}$

${\large{\blue{\bold{\underline{Given:-}}}}}$

$\sf\implies \frac{1}{ \sqrt{9} - \sqrt{8} } \\ \\ = \sf \frac{1}{ \sqrt{9} - \sqrt{8} } \times \frac{ \sqrt{9} + \sqrt{8} }{ \sqrt{9} + \sqrt{8} } \\ \\ = \sf \frac{ \sqrt{9} + \sqrt{8} }{( \sqrt{9} ) {}^{2} - ( \sqrt{8}) {}^{2} } \\ \\ = \sf \frac{ \sqrt{9} + \sqrt{8} }{9 - 8} \\ \\ = \sf \frac{ \sqrt{9} + \sqrt{8} }{1} \\ \\ \sf\huge\fbox\red{ = \sqrt{9} + \sqrt{8}}$