1/{root of (11-2 root 30)}-3/{root of(7-2 root 10)}-4/{root of (8+4 root 3)}
please solve this fast...
Answers
1 - 3 - 4
√(11 - 2√30) √(7 - 2√10) √(8 + 4√3)
a = 1/√(11 - 2√30)
a² = 1² = 1
(√(11 - 2√30)² 11 - 2√30
b = 3
3√(7 - 2√10)
b² = 3² = 9
(√7 - 2√10)² 7 - 2√10
c = 4/ √(8+4√3)
c² = 4 = 16
√(8 +4√3) 8 + 4√3
1 - 9 - 16
11 - 2√30 7 - 2√10 8 + 4√3
11 + 2 √30 - 9 (7 + 2√10) - 16(8 - 4√3)
121 - 120 49 - 40 64 - 48
11 + 2 √30 - 9(7 + 2√10) - 16(8 - 2√3)
1 9 16
11 + 2√30 - 7 - 2√10 - 8 + 2√3
- 4 + 2√30 - 2√10 + 2√3
Refer to the above attachment !
Hope this help you
