Math, asked by adithisajith, 8 months ago

1/root3+root2 + 2/root3-root2 simplify

Answers

Answered by manyasachdeva60
1

Answer:

the answer is root 3.

I hope it helps u....

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Answered by arpitmahala76
0

HEY MATE ❤️❤️

Here Is Your Answer:-

 \frac{1}{ \sqrt{3} +  \sqrt{2}  } +  \frac{1}{ \sqrt{3} -  \sqrt{2}  }

 =  \frac{1( \sqrt{3} -  \sqrt{2} ) }{ (\sqrt{3} +  \sqrt{2} )( \sqrt{3} -  \sqrt{2})  }  +  \frac{1( \sqrt{3} +  \sqrt{2} ) }{( \sqrt{3} -  \sqrt{2})( \sqrt{3} +  \sqrt{2})   }

 =  \frac{ \sqrt{3} -  \sqrt{2}  }{( { \sqrt{3} )}^{2} - ( { \sqrt{2} )}^{2}   }   +  \frac{ \sqrt{3} + \sqrt{2}  }{( { \sqrt{3}) }^{2} - ( { \sqrt{2}) }^{2}  }

 =  \frac{ \sqrt{3} -  \sqrt{2}  }{3 - 2} +  \frac{ \sqrt{3} +  \sqrt{2}  }{3 - 2}

 = \frac{ \sqrt{3}   -   \sqrt{2}  }{1}  +  \frac{ \sqrt{3} +  \sqrt{2}  }{1}

 =  \sqrt{3} -  \sqrt{2} +  \sqrt{3}  +  \sqrt{2}

 =  \sqrt{3} +  \sqrt{3} +  \sqrt{2} -  \sqrt{2}

 =   \sqrt{3}  +  \sqrt{3}

 = 2 \sqrt{3}

hope it helps

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