Question

1)Root8*root18*root400

2)16^-1/4*4root16=_____

3)the value of x in 3+2^x=(64)^1/2+(27)1/3

4)4root81-
8(3root216)+15(5root32)+root225

Answer 1

3.)3+2^x=(64)½+(27)⅓
3+2^x=(8²)½+(3³)⅓
3+2^x=8+3
3-3+2^x=2³
2^x=2³
On equating the exponents we get
[x=3]ANSWER...
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