Math, asked by tenzingtsomo4567, 9 months ago

1/root9-root8 is equal to
a)⅓(3-2root2)
b)1/3+2root2
c)3-2root2
d)3+2root2​

Answers

Answered by masthanjavidvali4962
4

Answer:

1/(√9-√8)

=>1/(3-2√2)

by rationalisation

=>(3+2√2)/9-8

=>3+2√2

there fore the answer is

d)3+2root2

Similar questions