Math, asked by Kartikkumarnayak, 11 months ago

1. Round off 43, 98 and 236 to the nearest ten. After rounding off, add them. Round off the
sum to the nearest hundred.
2. Round off 731 and 164 to the nearest ten. Find the difference of the rounded off numbers.
Round off the difference to the nearest hundred.
3. A 2-digit number was rounded off to the nearest ten and the result was 60. Find the interval
of the original number.
4. A 3-digit number was rounded off to the nearest ten and the result was 320. Find the
interval of the original number.

Answers

Answered by rotik
17
1. 380. 2. 570. 3. 55to 65. 4. 315to325
Answered by sasan
24

Answer:

1) 400 2) 600 3) 55 to 59 and 60 to 64 4) 315 to 319 and 520 to 324 

Step-by-step explanation:

Rules:if the number you are supposed to round is 5,6,7,8,9 then round it up.   Example: 68 to the nearest ten, then it would be 70.However, if it is 0,1,2,3,4, round it down. Example: 64 to the nearest ten, then it would be 60.

1) 43 to 40, 98 to 100, 236 to 240 (rounding to the nearest ten)

  40 + 100 + 240 = 380

  380 rounded to the nearest hundred is 400

2) 731 to 730, 164 to 160 (rounding to the nearest ten)

   730 - 160 = 570

   570 rounded to the nearest hundred is 600

3) if the result of rounding a two-digit number to the nearest ten result in 60, then there is a possibility that the number before it was rounded could range from 55 to 59 and 60 to 64.

4) If the result of rounding a three-digit number to the nearest ten result in 320, then the possibility of the original number range from 315 to 319 and 320 to 324.

Similar questions