Math, asked by morankargajanan359, 4 months ago

1. Sameerrao has taken a loan of 12500 at a rate of 12 p.c.p.a. for 3 years. If the
interest is compounded annually then how many rupees should he pay to clear
his loan.
2. To start a business Shalaka has taken a loan of 8000 at a rate of 10
1/2 p.c.p.a.
After two years how much compound interest will she have to pay ? ​

Answers

Answered by Anonymous
18

Answer:

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrs

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 years

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = A

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿ

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿA = 8000 ( 1 + 21/200 )²

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿA = 8000 ( 1 + 21/200 )²A = 8000 ( 221/200 )²

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿA = 8000 ( 1 + 21/200 )²A = 8000 ( 221/200 )²A = ( 8000 × 48841 )/ 40000

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿA = 8000 ( 1 + 21/200 )²A = 8000 ( 221/200 )²A = ( 8000 × 48841 )/ 40000A= Rs 9768.20

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿA = 8000 ( 1 + 21/200 )²A = 8000 ( 221/200 )²A = ( 8000 × 48841 )/ 40000A= Rs 9768.20Compound Interest ( C . I ) = A - P

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿA = 8000 ( 1 + 21/200 )²A = 8000 ( 221/200 )²A = ( 8000 × 48841 )/ 40000A= Rs 9768.20Compound Interest ( C . I ) = A - P= Rs 1768.20

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿA = 8000 ( 1 + 21/200 )²A = 8000 ( 221/200 )²A = ( 8000 × 48841 )/ 40000A= Rs 9768.20Compound Interest ( C . I ) = A - P= Rs 1768.20I hope this helps you.

1) Hence, he should pay an amount of ₹ 17561.60 to clear his loan.2) It is given that ,principal ( p ) = Rs 8000Rate of interest ( R ) = 10½ % p.a = 21/2 yrsTime ( T ) = 2 yearsnumber of times interest paid = n = 2Amount = AA = P( 1 + R/100 )ⁿA = 8000 ( 1 + 21/200 )²A = 8000 ( 221/200 )²A = ( 8000 × 48841 )/ 40000A= Rs 9768.20Compound Interest ( C . I ) = A - P= Rs 1768.20I hope this helps you.: )

3)

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