Question

1 . Savita and Hamida are friends. What is the probability that both will have (i) different birthdays? (ii) the same birthday? (ignoring a leap year).​

Answer 1

Answer:

1

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365

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Answer 2

Answer:

savita can take birth on any of the 365 days with prob. 1

now in order to have the same birthday hamida should take birth on the same day i.e say if savita birthday is 15 march then hamida birthday should be 15 march i.e out of 365 days hamida can take birth in one way so prob =1/365

prob of same birthday = 1/365

prob of different bday= 1–1/365 = 364/365.

think intuitively if savita bday i 15 march then hamida cant take birth on 15 march i.e. she has 364 days out of 365 days to take birth so prob of different bday= 364/365

Step-by-step explanation:

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