Math, asked by kanyasankhla8143, 10 months ago

1/sec 0 - tan 0 = seco + tano

Answers

Answered by shivayogesh1102

0

Step-by-step explanation:

LHS:

= 1/secx - tanx

multiply secx+tanx on both numerator and denominator

=secx+tanx/sec^2x-tan^2x. [sec^2x - tan^2x = 1]

=secx + tanx

Answered by yogesh696

0

rationale it and solve it

thanku

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