1/sec 0 - tan 0 = seco + tano
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Step-by-step explanation:
LHS:
= 1/secx - tanx
multiply secx+tanx on both numerator and denominator
=secx+tanx/sec^2x-tan^2x. [sec^2x - tan^2x = 1]
=secx + tanx
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rationale it and solve it
thanku
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