Question

1/sec^2-cos^2. +. 1/cosec^2-sin^2. *sin^2 * cos*2 =1-sin^2* cos^2/2+ sin^2* cos^2

Answer 1

Step-by-step explanation:

Prove that [1/(sec2θ-cos2θ)+1/(cosec2θ-sin2θ)]sin2θcos2θ=(1-sin2θcos2θ)/(2+sin2θcos2θ). Prove that [1/(sec2 theta-cos2 theta)+1/(cosec2 theta-sin2 ...