Math, asked by divyansh88098, 5 months ago


[1/(sec^2thita-cos^2theta) + 1/(cosec^2theta-sec^2theta)]*sin^2theta*cos^2theta​

Answers

Answered by shrutimahato8
0

Answer:

1 - sin^2theta cos^2theta /2+sin^2theta cos^2 theta

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