Question

ꜱᴇᴄ ᴛʜᴇᴛᴀ +ᴄᴏꜱ ᴛʜᴇᴛᴀ = 1, sec^3ᴛʜᴇᴛᴀ +cos^3 ᴛʜᴇᴛᴀ =
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Answer 1

Answer:

sec^3T+cos^3T= (sec+cos)(sec^2+cos^2-sec.cos)

=1×(sec^2+cos^2+1)

=sec^2+cos^2+2-2+1

=sec^2 +cos^2+2sec.cos-2+1

(since sec×cos=1)

=(sec+cos)^2 -1

=(1)^2-1

=1-1=0 Ans