Question

1. sec 50° sin 40° + cos 40° cosec 50°​

Answer 1

Answer:

sec 50° sin 40° + cos 40° cosec 50°

$\frac{1}{ \cos(50 {}^{0} ) } \times \sin(40 {}^{0} ) + \cos(40 {}^{0} ) \times \frac{1}{ \sin(50 {}^{0} ) }$

cos50⁰ = sin(90⁰-50⁰) = sin 40⁰

sin50⁰ = cos(90⁰-50⁰) = cos40⁰

$\frac{1}{ \sin(40 {}^{0} ) } \times \sin(40 {}^{0} ) + \cos(40 {}^{0} ) \times \frac{1}{ \cos(40 {}^{0} ) }$

1 + 1 = 2

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