Question

1+sec a/ sec a=sin 2a/1-cos a

Answer 1

hope it's clear to you..

Answer 2

Answer:

L.H.S = R.H.S

Step-by-step explanation:

According to this question

Given that,

$\frac{1 + sec a}{sec a}$ = $\frac{sin 2a}{1 - cos a}$

Let, L.H.S

$\frac{1 + sec a}{sec a}$

$\frac{1 + (\frac{1}{cos a})}{\frac{1}{cos a}}]$

$\frac{\frac{cos a + 1}{cos a}}{\frac{1}{cos a}}$

$cos a + 1$

Multiple and divide with (1 - cos a)

$(1 + cos a)\times \frac{1 - cos a}{1 - cos a}$

$\frac{1 - cos^2 a}{1 - cos a}$

$\frac{sin 2a}{1 - cos a}$

R.H.S