Question

1+ sec A/secA=SINsquareA/1-cos



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Answer 1

$LHS \: \: \: \\ \frac{1 + seca}{seca} \\ = \frac{1 + \frac{1}{cosa} }{ \frac{1}{cosa} } \\ = 1 + cosa \\ RHS \: \: \: \frac{ {sin}^{2}a }{1 - cosa} \\ = \frac{1 - {cos}^{2} a}{1 - cosa} \\ = 1 + cosa$

LHS=RHS