Question

1 + sec A sin? A IL (iv) [Hint : Simplify LHS and RHS separately) sec A 1 - COS A cos A sin A +1 ​

Answer 1

Step-by-step explanation:

(1+secA)/secA = sin²A/(1-cosA)

solving LHS

(1+secA)/secA=1/secA + 1=cosA+1

soling RHS

sin²A/(1-cosA)

=(1-cos²A)/(1-cosA)

=1+cosA

LHS=RHS